Question 390462
Note that for every increase of 2 for x, y increases by 3. The function is (most probably) linear, with slope of 3/2. Plugging any point (x,)) into {{{y = (3/2)x + b}}}, we obtain b = 2, so the equation of the line is {{{y = (3/2)x + 2}}}.


I say that it is most probably linear because it is possible to define an unusual function that satisfies all the given x,y values. For example, the function {{{y = (3/2)x cos (x*pi) + 2}}} is equivalent to {{{y = (3/2)x + 2}}} at the given values, but nowhere else on the function. If we already know the function is linear, then you can be sure that {{{y = (3/2)x + 2}}} is the only function that satisfies.