Question 390456
{{{(1/6) (y+42)-15=-3 }}} Start with the given equation.



{{{(1/6)y+(1/6)42-15=-3 }}} Distribute



{{{(1/6)y+7-15=-3 }}} Multiply



{{{6((1/cross(6))y+7-15)=6(-3)}}} Multiply both sides by the LCD {{{6}}} to clear any fractions.



{{{y+42-90=-18}}} Distribute and multiply.



{{{y-48=-18}}} Combine like terms on the left side.



{{{y=-18+48}}} Add {{{48}}} to both sides.



{{{y=30}}} Combine like terms on the right side.



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Answer:


So the solution is {{{y=30}}} 



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