Question 42589
Solve:
{{{x^2-4x-5 = 0}}} This is factorable so you can solve it by factoring.
{{{(x+1)(x-5) = 0}}} Apply the zero products principle.
{{{x+1 = 0}}} and/or {{{x-5 = 0}}}
If {{{x+1 = 0}}} then {{{x = -1}}}
If {{{x-5 = 0}}} then {{{x = 5}}}

The roots are:
x = -1
x = 5