Question 390193
A man standing on top of a building sees an automobile on a street below him.The angle of depression is 26degrees 22'.If his eye is 550 ft above the level of the automoile, how far is the automobile for him.
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draw a sketch
a rectangle ABCD
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A man
B vertical point below the man
C= car position
D = vertical position above car in line with A
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We have to find length AC.
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angle DAC = angle of depression = 26deg.22'
this is = angle ACB . alternate angles
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sine angle ACB = vertical / hypotenuse (AC)
sine 26 degrees 22 minutes = 550/AC
AC = 550/sine 26 degrees 22 minutes
AC = 1238 feet
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m.ananth@hotmail.ca