Question 390134
{{{-5y^4(y^5)^2 / 15y^7(y^2)^3}}}
Cancel the 5
= {{{-y^4(y^5)^2 / 3y^7(y^2)^3}}}
Expand
= {{{-y^4*y^10 / (3y^7*y^6)}}}
= {{{-y^14/3y^13}}}
= {{{-y/3}}}
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Was your answer (-1/3)y ?  That's correct.
Or, -1/(3y) ?  That's wrong.