Question 390118
log(base 3)x+log(base 3)(2x)-log(base 3)(x+3)=1
{{{log(3,x) + log(3,2x) - log(3,(x+3)) = 1}}}
{{{log(3,(x*2x/(x+3))) = 1}}}
x*2x/(x+3) = 3
{{{2x^2 = 3x + 9}}}
{{{2x^2 - 3x - 9 = 0}}}
(2x + 3)(x - 3) = 0
x = 3
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x = -3/2 *** has to be rejected since you can't take a log of a negative number.