Question 390071
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Hi,        
2x^2+10x+k=0 when x = -2
 2(-2)^2 + 10*(-2) + k = 0
    8 - 20 + k = 0
            k = 12

2x^2+10x+12=0
2(x^2 + 5x + 6) = 0
(x^2 + 5x + 6) = 0
factoring
( x+2)(x+ 3)= 0 Note:SUM of the inner product(2x) and the outer product(3x) = 5x
( x+2)= 0
    x = -2  Already determined
(x+ 3)= 0
    x = -3, the other root