Question 390063
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Hi,        
solving the following using the Quadratic formula
3x^2-48=0   Note b = 0, in this example
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (0 +- sqrt( 576 ))/(6) }}}
{{{x = (0 +- 24)/(6) }}}
  x = ± 4

Note: Solving by factoring
3x^2-48=0  
3(x^2-16)=0  
3(x-4)(x+4)=0  
(x-4)=0
   x = 4
(x+4)= 0
   x = -4