Question 389878
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Hi,  
Using the Quadratic Formula:  
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}   
x^2 - 6x + 10 = 0  {{{x = (6 +- sqrt( -4 ))/(2) = 3 +- i }}}
x^2 - 6x - 10 = 0  {{{x = (6 +- sqrt( 76 ))/(2) }}}
x^2 - 6x + 8 = 0  (x-2)(x-4)= 0 or {{{x = (6 +- sqrt( 4 ))/(2) }}}
x^2 - 6x - 8 = 0   {{{x = (6 +- sqrt(68 ))/(2) }}}