Question 389842
The denominator of the fraction is 2 more than the numerator. If 1 is subtracted from both numerator and denominator, the resulting fraction has a value of 1/2. Find the original fraction.
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let numerator be x
denominator = (x+2)
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1 is subtracted from both
numerator = x-1
denominator = (x+2)-1=x+1
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The fraction ={{{(x-1)/(x+1)}}}
={{{(x-1)/(x+1)}}}=1/2
2(x-1)=(x+1)
2x-2=x+1
2x-x=2+1
x=3
so denominator = 3+2=5
The fraction = {{{3/5}}}
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