Question 389785
the width of the walk is added to both ends of the length and width of the pool
this makes the dimensions of the pool/walk 6+2w by 10+2w
the area is twice the area of the pool ___ a = 6 * 10 * 2 = 120


(6 + 2w)(10 + 2w) = 120


4w^2 + 32w + 60 = 120


w^2 + 8w - 15 = 0


use quadratic formula to find w