Question 389745
What would the polynomial with real coefficients 
whose zeroes are -4, 1-i, and 1 + i be?
----
f(x) = (x+4)(x-(1-i))(x-(1+i))
----
f(x) = (x+4)((x-1)+i)((x-1)-i)
----
f(x) = (x+4)((x-1)^2+1)
---
f(x) = (x+4)(x^2-2x+2)
---
f(x) = x^3+2x^2-4x+8

===========================
Cheers,
stan H.