Question 389720
If {{{f(x) = (e^x)(ln x)}}}, then by the Product Rule,


f'(x) = {{{(e^x)(ln x) + (e^x)(1/x)}}} (somehow the parsing system doesn't accept f'(x) so I put it outside)


Replacing x with e,


f'(e) = {{{e^e + (e^e)(1/e) = e^e + e^(e-1)}}}