Question 389730
The area is simply {{{int(88 - 16x^2, dx, 0, 2.3)}}} where x represents time. The indefinite integral {{{int(88 - 16x^2, dx)}}} is equal to {{{88x - 16x^3/3}}} by the Power Rule. Evaluate it at x = 2.3 and subtract the value obtained at x = 0.


However...I'm a little confused as to why we integrate position.