Question 389718
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Hi,         
{{{(1-y)/(1+y) =2/3 }}} Cross Multiplying
 2(1+y) = 3(1-y)
 2 + 2y = 3 - 3y
     5y = 1
      y = 1/5
CHECKING our Answer
 2 * 6/5 = 3*4/5 = 12/5

{{{(x-2)/(x+1) = (x+1)/(x-2)}}} Cross Multiplying
 (x+1)(x+1) = (x-2)(x-2)
x^2 + 2x + 1 = x^2 -4x + 4
         6x = 3
          x = 1/2
CHECKING our Answer
 -3/2 / 3/2 = 3/2/-3/2 = -1

{{{3x/(x-2) = 6/(x-2)}}} Cross Multiplying
  6(x-2) = 3x(x-2)
 6x -12 = 3x^2 - 6x
 3x^2 -12x + 12 = 0
x^2 - 4x + 4 = 0
(x - 2)(x-2) = 0
(x - 2)= 0
(x - 2) = 0
    x = 2  Solution undefined as zero cannot be a denominator
m = f/a, for a    a = f/m
E/R + r = I, for R   
E/R = I - r
E = R(I-r)
E/(I-r) = R