Question 389657
x+3y=2_-2x-4y=2

Since 3y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 3y from both sides.
x=-3y+2_-2x-4y=2

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -3y+2.
x=-3y+2_-2(-3y+2)-4y=2

Multiply -2 by each term inside the parentheses.
x=-3y+2_6y-4-4y=2

Since 6y and -4y are like terms, add -4y to 6y to get 2y.
x=-3y+2_2y-4=2

Since -4 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 4 to both sides.
x=-3y+2_2y=4+2

Add 2 to 4 to get 6.
x=-3y+2_2y=6

Divide each term in the equation by 2.
x=-3y+2_(2y)/(2)=(6)/(2)

Simplify the left-hand side of the equation by canceling the common factors.
x=-3y+2_y=(6)/(2)

Simplify the right-hand side of the equation by simplifying each term.
x=-3y+2_y=3

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 3.
x=-3(3)+2_y=3

Multiply -3 by each term inside the parentheses.
x=-9+2_y=3

Add 2 to -9 to get -7.
x=-7_y=3

This is the solution to the system of equations.
x=-7_y=3