Question 389645

{{{-5x^2 + 2x +3 = 0}}}........ multiply by {{{-1 }}}to change each sign

{{{5x^2 -2x -3}}}

 then we factor

*[invoke change_this_name4450 5, -2, -3, "x"]



{{{(5x+3)(x-1)}}}...set to zero

{{{(5x+3)(x-1)=0}}}........product is equal to zero if at least one or both factors are equal to zero, so you will have

{{{5x+3=0}}}.....->{{{5x=-3}}}.....->{{{x=-3/5}}}....or

{{{x-1=0}}}......->{{{x= 1}}}...


the answer is: {{{x = -3/5}}} or {{{x = 1}}}


another way to check the result:

*[invoke quadratic_formula 5, -2, -3, "x"]