Question 389611
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Hi,         
Using the quadratic formula 
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
 x^2+x-20 = 0
{{{x = (-1 +- sqrt( 81))/(2) }}}
{{{x = (-1 +-9 )/(2) }}}  x = -10/2 = -5 and x = 8/2 = 4
 x^2 - 5x + 6 = 0 
{{{x = (5 +- sqrt( 1))/(2) }}}
{{{x = (5 +- 1)/(2) }}}   x = 6/2 = 3 and x = 4/2 = 2