<PRE><B>Question 389571</B>
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Hi
Let x and (x+2) and (x+4)
represent the first, second and third of three consecutive odd numbers
Question States***
 (1/7) x + 1/3(x+2) +1/5(x+4) = 63
solving for x
Multiplying all terms by 105, so as all denominators = 1
 15 + 35(x+2) + 21(x+4) = 63*105
  71x + 154 = 6615
  71x = 6461
     x = 91  Three  consecutive even numbers  are 91,93,95
CHECKING our Answer***
 1/7*91 + 1/3*93 + 1/5*95 = 13 + 31 + 19 = 63</PRE>