Question 389595
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Hi,         
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
10.3% of students in statistics actually take the course because they want to
In this case p = .103 & q = .897
nCx = {{{n!/(x!(n-x!))}}}
P( 2 randomly selected, taking stat because they wanted to) = (.103)^2 = .0106