Question 389518
how to solve (-10,-5) and (-8,-2) with the equation y-y1=m(x-x1)


Obviously, you need to create, not solve an equation in y = mx + b format, using the coordinates (-10, - 5) and (-8, - 2).


Find the slope or m: {{{(y[2]-y[1])/(x[2]-x[1])}}}...... {{{(-2--5)/(-8--10))}}}......{{{(-2+5)/(-8+10)}}}......{{{3/2}}}


With m, or slope = {{{3/2}}} and one coordinate point (-8, - 2), we can use the point-slope formula to determine the linear equation:  {{{y - y[1] = m(x - x[1])}}}__{{{y - - 2 = (3/2)(x -- 8)}}}__{{{y + 2 = (3/2)(x + 8)}}}__{{{y + 2 = (3/2)x + 12}}}__{{{highlight_green(y = (3/2)x + 10)}}}