Question 42460
length = 1 + w
width = w
Pythagoras Theorm:
{{{a^2 + b^2 = c^2}}}
{{{(1 + w)^2 + (w)^2 = (4)^2}}}
{{{1 + 2w + w^2 + w^2 = 16}}}
{{{2w^2 + 2w - 15 = 0}}}
a=2 b=2 c=-15
{{{w = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{w = (-2 +- sqrt( 2^2-4*2*(-15) ))/(2*2) }}}
{{{w = (-2 +- sqrt( 124 ))/(4) }}}
{{{w = (-1/2) +- sqrt(124)/4}}}
*[invoke quadratic "w", 2, 2, -15]
Answer: {{{w = (-1/2) + sqrt(124)/4}}}
length: {{{l = 1 + (-1/2) + sqrt(124)/4}}}