Question 389520
2x+y=5

To find the x-intercept, substitute in 0 for y and solve for x.
2x+(0)=5

Remove the parentheses around the expression 0.
2x+0=5

Remove the 0 from the polynomial; adding or subtracting 0 does not change the value of the expression.
2x=5

Divide each term in the equation by 2.
(2x)/(2)=(5)/(2)

Simplify the left-hand side of the equation by canceling the common factors.
x=(5)/(2)

To find the y-intercept, substitute in 0 for x and solve for y.
2(0)+y=5

Multiply 2 by each term inside the parentheses.
0+y=5

Solve the equation.
y=5

These are the x and y intercepts of the equation 2x+y=5.
x=(5)/(2), y=5





3x*4y=13

To find the x-intercept, substitute in 0 for y and solve for x.
3x*4(0)=13

Multiply 3x by 4 to get 12x.
12x(0)=13

Multiply 12x by each term inside the parentheses.
0=13

Since 0$13, there are no solutions.
No Solution

To find the y-intercept, substitute in 0 for x and solve for y.
3(0)*4y=13

Multiply 3 by 4y to get 12y.
12y(0)=13

Multiply 12y by each term inside the parentheses.
0=13

Solve the equation.
No Solution

These are the x and y intercepts of the equation 3x*4y=13.
No x or y intercepts.




I was not sure if each are seperate or you needed solving by using the Graphing Method to solve; if so:

3x*4y=13_2x+y=5

Multiply 3x by 4y to get 12xy.
12xy=13_2x+y=5

Divide each term in the equation by 12x.
(12xy)/(12x)=(13)/(12x)_2x+y=5

Simplify the left-hand side of the equation by canceling the common factors.
y=(13)/(12x)_2x+y=5

Since 2x does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2x from both sides.
y=(13)/(12x)_y=-2x+5

Create a graph to locate the intersection of the equations.  The intersection of the system of equations is the solution.
y=(13)/(12x)_y=-2x+5