Question 389519
x+y=2_y=2x-1

Since y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting y from both sides.
x=-y+2_y=2x-1

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -y+2.
x=-y+2_y=2(-y+2)-1

Multiply 2 by each term inside the parentheses.
x=-y+2_y=-2y+4-1

Subtract 1 from 4 to get 3.
x=-y+2_y=-2y+3

Since -2y contains the variable to solve for, move it to the left-hand side of the equation by adding 2y to both sides.
x=-y+2_y+2y=3

Since y and 2y are like terms, add 2y to y to get 3y.
x=-y+2_3y=3

Divide each term in the equation by 3.
x=-y+2_(3y)/(3)=(3)/(3)

Simplify the left-hand side of the equation by canceling the common factors.
x=-y+2_y=(3)/(3)

Simplify the right-hand side of the equation by simplifying each term.
x=-y+2_y=1

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 1.
x=-(1)+2_y=1

Multiply -1 by the 1 inside the parentheses.
x=-1+2_y=1

Add 2 to -1 to get 1.
x=1_y=1

This is the solution to the system of equations.
x=1_y=1