Question 389503
To remove {{{i-terms}}} on the denominator, you multiply above and below by the complex conjugate of the denominator (in this case {{{(3-i)}}}):

{{{2 / (3 + i) = 2 / (3 + i) * (3 - i)/(3 - i)}}}
= {{{2(3 - i) / (3 + i)(3 - i)}}}
= {{{2(3 - i) / (3^2 -i^2)}}}
= {{{2(3 - i) / (3^2 +1) }}}[ take extreme care with -i^2]
= {{{2(3 - i) / 10}}}
= {{{(3 - i) / 5}}}