Question 389432
The parabola can be defined by the form:
y=A(x-h)^2+k, h,k representing the (x,y) coordinates of the vertex
with the given y-intercept coordinates (0,-3) and vertex coordinates(1,1)
-3=A(0-1)^2+1
A=-4
equation of parabola: y=-4(x-1)^2+1
=-4(X^2-2x+1)+1 =-4x^2+8x-3
to find x-intercept, set y=0
0=-4(x-1)^2+1
4(x-1)^2=1
(x-1)^2=1/4
taking sqrt of both sides,
x-1=±1/2
x=1/2 or 3/2

ans: x -intercepts at 1/2 and 3/2
 
{{{ graph( 300, 200, -6, 5, -10, 10, -4x^2+8x-3) }}}