Question 389463
Let A be the amount of 14% alcohol.
Let B be the amount of 22% alcohol.

We know the total amount is 200 ml, so:

A + B = 200
Solving for A (picked at random):
A + B - B = 200 - B
A = 200 - B

Now we form another equation based on the amount of alcohol each solution contributes and the final amount:

.14 * A + .22 * B = .176 * 200

.14A + .22B = 35.2
Multiplying everything by 100 to work with whole numbers:
14*A + 22*B = 3520

Substiture the value of A from the first equation:

14*(200 - B) + 22*B = 3520
2800 - 14*B + 22*B = 3520
2800 + 8*B = 3520
8*B = 3520 - 2800
8*B = 720
B = 90

Substituting the value of B back into the first equation:

A = 200 - B
A = 200 - 90
A = 110