Question 389459
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Hi,         
  y^3 - 64
  y^3 -4^3  perfect cube. 
In general: x^3 - a^3 = (x-a)(x^2 + ax + a^2)
   y^3 -4^3 
Factors to:  with  a = 4
  (y-4)(y^2 + 4y + 16)