Question 389455
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Hi
5/(2x^2-2) -  4/(3x^2-3x-6)
5/[2(x^2-1)] -  4/[3(x^2-x-2)]
{{{5/(2(x-1)(x+1)) -  4/(3(x-2)(x+1))}}}  LCD is 6(x-1)(x-2)(x+1)
[5*3(x-2) - 4*2(x-1)] / 6(x-1)(x-2)(x+1)
[15(x-2) - 8(x-1)] / 6(x-1)(x-2)(x+1)
(7x - 22)/ 6(x-1)(x-2)(x+1)