Question 389445
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Hi,         
geometric series -3/2, 1,-2/3,+... 
{{{a[n] = a[1]*r^(n-1)}}} In this example r = -2/3

{{{a[4] = (-3/2)*(-2/3)^3 = -3/2*-8/27 = 4/9}}}
{{{a[5] = (-3/2)*(-2/3)^4 = -3/2*16/81 = -8/27}}}
-3/2 + 1 + -2/3 + 4/9 - 8/27 = ( -81 + 54 -  36 + 24 - 16) /54 = -55/54