Question 389432
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Hi,  
the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
vertex (1,1)
y =a(x-1)^2 +1
using y-intercept pt(0,3) to find a
3 = a(-1)^2 + 1
2 = a
y = 2(x-1)^2 + 1  OR y = 2[x^2 - 2x +1] + 1
 Vertex Pt(1,1) in the minimum point for the parabola (a>0) 
parabola does not intercept the x-axis
{{{graph( 300, 300, -20,20,-20,20, 2(x-1)^2 + 1 ))}}}