Question 389393
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Hi,         
three positive integers are (x-1),x and (x+1) 
Write as we Read***
 x(x-1)(x+1) = 40[(x-1)+ x +(x+1)]
 x(x-1)(x+1) = 40[3x]
  (x-1)(x+1) = 120
Solving for x
   x^2 - 1 = 120
     x^2 = 121
     x = 11 (tossing out negative solution) Positive integers are 10,11,12

CHECKING our Answer***
  1320 = 40* 33