Question 389383
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Hi,         
16^2-x=8^3x
 {{{(2^4)^(2-x) = (2^3)^(3x)}}}
 {{{2^(4(2-x)) = 2^(3(3x))}}}
   4(2-x) = 9x
    8 - 4x = 9x
       8 = 13x
       8/13 = x