Question 389378
a rectangle has a length one foot longer than twice the width. the area of the rectangle is 253 square feet. find the (a) length and (b) width.
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the unknowns are the length & width.
but they have a relation.
let width be x feet
length will be 2x+1
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L*W=Area
x(2x+1)= Area
x(2x+1)= 253
2x^2+2x= 253
-253
2x^2+2x-253=0
solve for roots using quadratic equation.
a=2,b=2,c-253
b^2-4ac=2028
{{{x1=(-2+sqrt(2028))/(2*2)}}}
width = 10.758 feet
{{{x2=(-2-sqrt(2028))/(2*2)}}}
This is negative so it is not practical
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width = 10.76
length = (2x+10
Length = 2*(10.76+1)
Length = 23.52 feet
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CHECK
23.52*10.76=253.07
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m.ananth@hotmail.ca