Question 389206
I really need to answer these trigonometry problems.
1. The measure of two of the angles of a triangle are 50 degrees and 55 degrees. If its longest side measures 17 cm, find the perimeter of the triangle.
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The measure of the third angle is 180-(50+55) = 75 degrees
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Find the length of the side opposite the 50 degree angle.
Use the Law of Sines:
a/sin(50) = 17/sin(75) 
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a = sin(50)[17/sin(75)]
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a = 13.48
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Find the length of the side opposite the 55 degree angle.
Use the Law of Sines:
b/sin(55) = [17/sin(75)]
b = sin(55)[17/sin(75)]
b = 14.42
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Perimeter: 17 + 13.48 + 14.42
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2. The vertex angle of an isosceles triangle is 72 degrees and each of the equal sides is 10 cm. Find the perimeter and area of the triangle.
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Use the Law of Sines as in problem #1.
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3. The diameter of a circle C is 34 cm. Two radii AC and BC form the angle of 96 degrees. Find the length of the cord AB.
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Perimeter = (pi)d = 34pi
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arc = (96/360)(34pi) = 28.48...cm
Cheers,
Stan H.