Question 389268
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Hi,  
 a father is four times as old as the sum of the ages of his two sons      
Let x and 4x represent the sum of son's ages and father's age NOW
Question States***
 4x + 8 = 2[x+16]
Solving for x
 4x + 8 = 2x + 32
    2x = 24
     x = 12, the sum of the two son's ages NOW.  Father is 48.  (4*12)

CHECKING our Answer***(8 years from NOW)
 56 = 2*28 = 56