Question 389246
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Hi,         
Finding the x-intercepts defined by the equation: y =3x^2+3x-6
 3x^2 + 3x - 6 = 0   Note: y = 0 where the parabola crosses x-axis
 3(x^2 + x - 2)= 0
 Factoring
 (x+2)(x-1)=0 Note:SUM of the inner product(2x) and the outer product(-x) = 1*x
 (x+2)= 0
   x = -2
 (x-1)= 0 
   x = 1
{{{drawing(300,300, -10,10,-10,10, grid(1),
circle(1, 0,0.3),
circle(-2, 0,0.3),
graph( 300, 300, -10,10,-10,10,3x^2+3x-6))}}}