Question 389224
  <pre><font size = 3 color = "indigo"><b>
Hi,         
Finding the roots
x^2-x-6 = 0
factoring
(x-3)(x+2)=0 Note:SUM of the inner product(-3x) and the outer product(2x) = -1x
(x-3)=0
 x = 3
(x+2)=0
 x = -2
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(3, 0,0.3),
circle(-2, 0,0.3),
graph( 300, 300, -6, 6, -6, 6,x^2-x-6))}}}