Question 389136



To find the {{{x}}} intercept you let {{{y=0}}} and solve for {{{x}}}, and 

to find the {{{y}}} intercept let {{{x=0}}} and solve for {{{y}}}.


in your case {{{y=c}}} and {{{x=j}}}

-the {{{x}}} intercept:

let {{{c=0}}

{{{0=j+1}}}

{{{-1=j}}}...or {{{j=-1}}}

so, the {{{x}}} intercept is (-1,0)


-the {{{y}}} intercept:

let {{{j=0}}

{{{c=0+1}}}

{{{c=1}}}

so, the {{{y}}} intercept is (0,1)