Question 389053
{{{2i/(4-3i)=(2i/(4-3i))*((4+3i)/(4+3i))}}}
{{{2i/(4-3i)=(8i+6i^2)/(16-12i+12i-9i^2)}}}
{{{2i/(4-3i)=(8i-6)/(16+9)}}}
{{{highlight(2i/(4-3i)=-(6/25)+(8/25)i)}}}