Question 388808
{{{1/(1-i*sqrt(3))^3}}}
={{{1/(2(1/2 - i*sqrt(3)/2))^3}}}
={{{1/(8*(cos(-60) + i*sin(-60))^3)}}}
={{{1/(8*(cos(-60) + i*sin(-60))^3)}}}
={{{1/(8*(cos(-180) + i*sin(-180)))}}} by de Moivre's Theorem
={{{1/(8*(-1+0))}}}
={{{-1/8}}}.