Question 388858
When a ball is thrown, its height in feet h 
after t seconds is given by the equation 
h(t) = vt-16t^2 where "v" is the initial 
upwards velocity in feet per second.
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If v = 36 feet per second, find all values of t for which h = 19 feet. 
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Solve: -16t^2+36t = 19
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-16t^2+37t-19 = 0
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t = [-37+-sqrt(37^2-4*-16*-19)]/(-32)
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t = [-37 +-sqrt(153)]/(-32)
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t = (-37+12.369..]/(-32) or t = (-37-12.369]/(-32)
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Positive solutions:
t = 0.8723 sec. and t = 1.4045 sec. 

Do not round any intermediate steps. Round your answer to decimal places.
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Cheers,
Stan H.
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