Question 387358
Given the linear equation y=-2/3x+1, find the y-coordinates of the points (-6,  ), (-3,  ), and (3,  ). Please show all of your work. Plot those points and graph the linear equation.
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Assuming you mean y=(-2/3)x+1  and not -2/(3x) + 1 or -2/(3x+1):
y=(-2/3)x+1
Sub 6 for x and find y
y = (-2/3)*6 + 1 = -3 --> (6,-3)
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x = -3:
y = 2 + 1 = 3 --> (-3,3)
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do the same for x = 3
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Plot the points, draw a line thru them.