Question 388748
The expression {{{x^2}}} is ALWAYS positive. Also, {{{abs(y-10)}}} is ALWAYS positive.



Because of this, this means that BOTH {{{x^2}}} and {{{abs(y-10)}}} must be values less than 1. However, if x is an integer, this would mean that x must be zero (because any other integer would make {{{x^2>1}}}). So this leaves the equation {{{abs(y-10)=1}}}. I'll let you solve it.



Alternatively, we can let {{{abs(y-10)=0}}} (using the same reasoning as above), which would leave us {{{x^2=1}}}. Again, I'll let you solve it.