Question 388706
3~(x+2)=6~(9x+10)    The ~stands for the square root of in this equation.

To remove the radical on the left-hand side of the equation, square both sides of the equation.
(3~(x+2))^(2)=(6~(9x+10))^(2)

Simplify the left-hand side of the equation.
(3)^(2)(x+2)=(6~(9x+10))^(2)

Expand the exponent of 2 to each factor in the expression 6~(9x+10).
(3)^(2)(x+2)=36(9x+10)

Multiply 36 by each term inside the parentheses.
(3)^(2)(x+2)=324x+360

Expand the exponent (2) to the expression.
3^(2)(x+2)=324x+360

Squaring a number is the same as multiplying the number by itself (3*3).  In this case, 3 squared is 9.
9(x+2)=324x+360

Multiply 9 by each term inside the parentheses.
9x+18=324x+360

Since 324x contains the variable to solve for, move it to the left-hand side of the equation by subtracting 324x from both sides.
9x+18-324x=360

Since 9x and -324x are like terms, add -324x to 9x to get -315x.
-315x+18=360

Since 18 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 18 from both sides.
-315x=-18+360

Add 360 to -18 to get 342.
-315x=342

Divide each term in the equation by -315.
-(315x)/(-315)=(342)/(-315)

Simplify the left-hand side of the equation by canceling the common factors.
x=(342)/(-315)

Simplify the right-hand side of the equation by simplifying each term.
x=-(38)/(35)