Question 388666
I'm assuming that the equation is {{{y=(3/2)x}}}. First swap x and y to get {{{x=(3/2)y}}} and then solve for y to get {{{y=(2/3)x}}}




If the equation on the other hand is {{{y=3/(2x)}}}, the same procedure is followed. Swap x and y to get {{{x=3/(2y)}}} and solve for y to get {{{y=3/(2x)}}}. In this case, the inverse is the same equation. 



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