Question 388552
3y+2/7ythird divide y-1/ysquare
Invert the divisor and multiply by it.
{{{((3y+2)/7y^3)*(y^2/(y-1))}}}
Cancel the y^2
= {{{((3y+2)/7y)*(1/(y-1))}}}
= {{{(3y+2)/(7y(y-1))}}}