Question 388631
The length of a rectangle is 2 feet less than its width. If the length is
increased by 4 feet, and the width is decreased by 2 feet, the area of the
new rectangle is 8 sq ft greater than the original. Find the area of the original rectangle.
width = x feet
length = x-2 feet
area = x(x-2) sq.ft
..
width x-2
length x-2+4=x+2
area = (x-2)(x+2)
..
(x-2)(x+2)-x(x-2)=8
x^2-4-x^2+2x=8
-4+2x=8
add 4
2x=12
/2
x= 6 feet the width
length = x-2 = 6-2 =4
...
area = 6*4 = 24 ft^2 --- Original rectangle
...
m.ananth@hotmail.ca