Question 388568
solve the linear system by using substituion
6x-y=-35
-6x   -6x
-y=-35-6x
/-1
y=6x+35
...
5x-2y=-35
substitute y in second equation
5x-2(6x+35)=-35
5x-12x-70=-35
-7x=70-35
-7x=35
/-7
{{{(highlight(x=-5))}}}
...
substitute the value of x 
6x-y=-35
6*-5-y=-35
-y=-35+30
-y=-5
y=5

{{{(highlight(y=5))}}}
...
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