Question 5366
-6z + 5-2(z+1)=3z-2
first do the parentheses:
-6z+5-2z-2=3z-2

Then combine like terms:
-8z+3=3Z-2

Add 8z to both sides of the equation:
3=11z-2

Add 2 to both sides of the equation:
5=11z

Divide both sides by 11
{{{(5/11)=z}}}

check by substituting {{{5/11}}} for z in the equation:
{{{-6z + 5-2(z+1)=3z-2}}}
{{{-6*(5/11)+5-2*(5/11+1)-2=(3*(5/11))-2}}}
convert everything to the same denominator to validate:
{{{-6*(5/11)+(55/11)-2*((5/11)+(11/11))=3*(5/11)-(22/11)}}}
{{{(-30/11)+(55/11)-(32/11)=(15/11)-(22/11)}}}
combine like terms:
{{{(-7/11)=(-7/11)}}}, So this is correct